Misc 8 Let A = 1−21−231115 verify that (i) adj A1 = adj (A1) First we will calculate adj (A) & A1 adj A = A11 A12 A13 A21 A22 A23 A31 A32 A33′= A11 A21 A31 A12 A22 A32 A13 A23 A33 A−5 Since cos(c) ≤1 and R 2n1(x) ≤ x2n2 (2n2)!Given the polynomial f (x) = 8 x 5
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1 500 pesos to dollars- Ex 122, 1 Find the distance between the following pairs of points (i) (2, 3, 5) and (4, 3, 1) Let P be (2, 3, 5) and Q be (4, 3, 1) Distance PQ = √((x2−x1)2(y2−y1)2(z2 −z1)2) Here, x1 = 2, y1 = 3, z1 = 5 x2 = 4, y2 = 3, z2 = 1 PQ = √((4−2)2(3−3)2(1 −5)2) =562 04 Lecture #13 page 2 Note splitting between vibrational levels εvib (v1)−=εθvib (v) k vib Recall energy (cm1) ~ 2/3 T (K) 1 ν ≈−400 4 000 cm ⇔θvib ≈600−6 K So for almost all molecules at room T, θvib >T Not in highT limit!
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Is the product of all positive integers from 1 1 1 to n − 1 n1 n − 1, the product must contain d d d and thus be divisible by d d d So we have (n − 1)!Click here👆to get an answer to your question ️ Find the value of the polynomial 5x 4x^2 3 at x = 1, 2, 2The average of the yearly change between 0610 is 2515(−30) 4 Wrong Interpretation " The average rate of change of people who emigrated from Ireland is 00 people per year
Z{3,1,4,2,5} = 31z−1 4z−2 2z−3 5z−4 = 3z4 1z3 4z2 2z 5)/z5 Z{2δn7δn−23δn−5} = 27z−2 3z−5 = (2z5 7z3 3)/z5 (2) Recall that the underline in the first example shows the location of time n = 0 The second example can beClick here👆to get an answer to your question ️ Show that A = satisfies the equation A^2 3A 7I = 0 and hence find A^1See answer › Systems of equations 1 Solve the system 5 x − 3 y = 6 4 x − 5 y = 12 \begin {array} {l} {5x3y = 6} \\ {4x5y = 12} \end {array} 5x−3y=6 4x−5y=12 See answer ›
NCERT Solutions for Class 12 Maths Chapter 2 Inverse Trigonometric Functions Again, cos y = √1−sin2 = √1−9 25 = 4/5 And tan y = sin y / cos y = ¾ Solve for tan(x y), using below identity,1 2 4 0 3 2 1 0 5 = −det 0 3 2 1 2 4 1 0 5 rows one and two interchanged det 1 2 4 0 3 2 1 0 5 = −det 1 4 2 0 2 3 1 5 0 columns two and three interchanged Corollary 41 If an n× n matrix has two identical rows or columns, its determinant must equal zero Proof The preceding theorem says that if you interchange any two rows or≡ 0 (m o d d) Also (n − 1)!
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27 If n is a positive integer then cos(nπ) = (−1)n Clearly 1 n1 < 1 n and lim n→∞ 1 n = 0 Therefore, the alternating series test implies that the series P cosnπ n converges 28 For n ≥ 3, the function f(n) = 1 2 n3 − 5 is positive;Lesson 28 Domain and Range of an Inverse Function 5 Example 2 List the domain and range of each of the following functions Then find the inverse function and list its domain and range a (𝑓𝑥)=−2 1−𝑥Given the polynomial f(x)=8x^5−5x^33x4, which one of the following is a possible rational root?
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316 Explain the difference between average velocity and instantaneous velocitySECTION 71 INTEGRATION BY PARTS ¤ 5 30 Let =arctan(1 ), = ⇒ = 1 1(1 )2 −1 2 − 2 1, = By(6), √ 3 1 arctan 1 = arctan 2 f (− 1) = (− 1) 2 = 1 f(1)=(1)^2=1 f (− 1) = (− 1) 2 = 1 so we'll have an open dot at (− 1, 1) (1,1) (− 1, 1) and f (2) = 2 2 = 4 f(2)=2^2=4 f (2) = 2 2 = 4 so we'll have a closed dot at (2, 4) (2,4) (2, 4) The third piece is the horizontal linear function of f (x) = 4 f(x)=4 f (x) = 4 from x = 2 x=2 x = 2 to infinity What
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26E Exercises for Section 25 In exercises 1 4, write the appropriate ε − δ definition for each of the given statements The following graph of the function f satisfies lim x → 2f(x) = 2 In the following exercises, determine a value of δ > 0 that satisfies each statement 5) If 0 < x − 2 < δ, then f(x) − 2 < 11 Compute T(−4,5,1) Solution T(−4,5,1) = (2∗(−4)5,2∗5−3∗(−4),−4−1) = (−3,22,−5) 2 Compute the preimage of w = (4,1,−1) Solution Suppose (v1,v2,v3) is in the preimage of (4,1,−1) Then (2v1 v2,2v2 −3v1,v1 −v3) = (4,1,−1) So, 2v1 v2 = 4 2v2 −3v3 = 1 v1 −v3 = −1 The augmented matrix of this system315 Describe the velocity as a rate of change;
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Find the product 1 2 (5 − 2 i) 1 2 (5 − 2 i) Multiplying Complex Numbers Together Now, let's multiply two complex numbers We can use either the distributive property or more specifically the FOIL method because we are dealing with binomials Recall that FOIL is an acronym for multiplying First, Inner, Outer, and Last terms together≡ 0 ≡ − 1≤10−5 which is satisfied when n≥3 Hence cos(x) ≈1− x2 2!
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